marley462847
05.03.2021 •
Mathematics
the value ax^2 + bx is 5 when x=1, and is equal to 0 when x=1.what are the values of a and b. explain how u arrived at your answer
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Ответ:
a = 1.25, b = 2.5, c = 1.25
Step-by-step explanation:
Use vertex form and substitute a point into it (1, 5)
5 = a(1 + 1)^2 + 0
5 = a(2)^2 + 0
5 = 4a
a = 5/4
y = 5/4 (x + 1)^2
y = 5/4 (x^2 + 2x + 1)
1.25 x^2 + 2.5x + 5/4
Is there a "c" value otherwise it's not possible
Ответ:
500 is the answer
Step-by-step explanation: