Mathematics: The velocity of a car increases from 4 m/s at 2 sec. To 32 m/s at 9 sec. What is the car’s average acceleration?

The velocity of a car increases from 4 m/s at 2

stephaniem0216

13.03.2021

$a=4\ m/s^2$

Step-by-step explanation:

Given that,

The velocity of a car increases from 4 m/s at 2 sec to 32 m/s at 9 sec.

We need to find the car's average acceleration. It can be given by the change in velocity divided by the change in time. So,

$a=\dfrac{v-u}{t_2-t_1}\\\\a=\dfrac{32-4}{9-2}\\\\a=4\ m/s^2$

So, the car's average acceleration is equal to $4\ m/s^2$ .

0,0(0 оценок)

saabrrinnaaa

03.08.2020

Part A: Geometric Sequence

Part B: $a_1 = 4, a_n = 2a_{n-1}$

Part C: a₈ = 512

Step-by-step explanation:

When we find the common ratio between the y-values (x-values are n inputs), we should see that we get r = 2. That means we have a geometric sequence.

Because we have a geometric sequence, our recursive formula is: $a_1, a_n=ra_{n-1}$ . Simply plug in our known variables:

$a_1 = 4, a_n = 2a_{n-1}$

Now we need to find what y is when x = 8, so (I used explicit formula):

$a_8 = 4(2)^{8-1}$

a_8=4(128)

a₈ = 512

0,0(0 оценок)