Mathematics: The vertex form of the equation of a parabola is y=(x-5)2+16.what is the standard form of the equation? a. y=x2-10x+41 b. y=x2+10x+16 c. y=x2+x+8 d. y=3x2-10x+41

distance is 5.o because you add both Step-by-step explanation:...

The vertex form of the equation of a parabola

preciadogabriel40

30.12.2021

Option (A) is correct.

The standard form of the equation of parabola y=(x-5)^2+16 is y=x^2-10x+41

Step-by-step explanation:

Given : The equation of a parabola is y=(x-5)^2+16

We have to find the standard form of the equation of parabola

Consider the equation of a parabola is y=(x-5)^2+16

Applying algebraic identity (a-b)^2=a^2+b^2-2ab

We have, a= x and b = 5

$(x-5)^2=x^2+5^2-2\cdot x\cdot 5$

Simplify, we have,

(x-5)^2=x^2-10x+25

Substitue, we have,

y=x^2-10x+25+16

Simplify, we have,

y=x^2-10x+41

Thus, The standard form of the equation of parabola y=(x-5)^2+16 is y=x^2-10x+41

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