Mathematics: The vertices of a triangle are A (-1,-4), B (2,-4) and C (2,-1). Use the distance formula and Pythagoras theorem to show that triangle ABC is an isosceles right-angled triangle

Answer (A) cuz of PMDAS p is first ...

The vertices of a triangle are A (-1,-4), B (2,-4)

evazquez

14.03.2021

Isosceles triangle

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are isosceles, equilateral, scalene and equilateral.

An isosceles triangle is a triangle with two equal sides and two equal angles.

The distance between two points $(x_1,y_1)\ and\ (x_2,y_2)$ on the coordinate plane is given by:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }$

Given a triangle with vertices A(-1,-4), B(2,-4) and C(2,-1). The sides of the triangle is given by:

$AB=\sqrt{(2-(-1))^2+(-4-(-4))^2}=3\\\\ AC=\sqrt{(2-(-1))^2+(-1-(-4))^2}=\sqrt{18}=3\sqrt{2} \\\\BC=\sqrt{(2-2)^2+(-1-(-4))^2}=3$

Since AB = BC, we can say that the triangle is an isosceles triangle.

0,0(0 оценок)