Mathematics: The weight gain of beef steers were measured over a 140 day test period. the average daily gains (lb/day) of 10 steers on the same diet were as follows. The tenth steer had a weight gain of 4.02 lb/day. 3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27 determine the mean and median.

The weight gain of beef steers were measured over

Ответ:

mibayla

04.08.2021

Mathematics

$\bar x = 3.545$

Median = 3.435

Step-by-step explanation:

Given

x:3.89, 3.51, 3.97, 3.31, 3.21, 3.36, 3.67, 3.24, 3.27

10th: 4.02

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{3.89 +3.51 +3.97 +3.31 +3.21 +3.36 +3.67 +3.24 +3.27+4.02}{10}$

$\bar x = \frac{35.45}{10}$

$\bar x = 3.545$

Solving (b): The median

First, we sort the data; as follows:

3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97, 4.02

n = 10

So, the median position is:

$Median = \frac{n + 1}{2}th$

$Median = \frac{10 + 1}{2}th$

$Median = \frac{11}{2}th$

Median = 5.5th

This means that the median is the average of the 5th and 6th item

$Median = \frac{3.36 + 3.51}{2}$

$Median = \frac{6.87}{2}$

Median = 3.435

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Ответ:

lil3114

03.08.2022

Mathematics

28+24=52
So we make a sum of what's going to equal 52 in small packets.
I found 4x13=52. 13 would be the number of packets
BUT!! Since it MUST be equal dark and milk and we have 28 and 26,
you would have to eliminate 1 pack because all 4 would be milk chocolate.
So that is only 12 packets.
4 per pack so that would be 2 dark and 2 milk per packet.

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The weight gain of beef steers were measured over a 140 day test period. the average daily gains (lb/day) of 10 steers on the same diet were as follows. The tenth steer had a weight gain of 4.02 lb/day. 3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27
determine the mean and median.

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