The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weighs 123 pounds when she is at sea level, 3960 miles from the center of Earth, how much will she weigh when she is at the top of a mountain, 3.2 miles above sea level?

Her weight is approximately 122.8lb

Step-by-step explanation:

Given

Inverse proportion;

Weight = 123lb when distance = 3960 miles from center of earth

Required

Calculate the weight when distance is 3.2 miles above sea level

Let weight be represented by W and distance by D

From the question, we understand that;

Weight is inversely proportional to square of distance;

Mathematically; this is

Convert proportion to equation

Where k is the constant of  proportionality

When W = 123; D = 3960.

This implies that

Make k the subject of formula

Calculating her weight when she's at the top of mountain, 3.2 miles above sea level

First, her distance from center of earth has to be calculated

Distance = Previous distance + 3.2

Distance = 3960 + 3.2

Distance = 3963.2

Now, her weight can be calculated using

Substitute for k and D

Length(l)= 2w
width(w)= w

Perimeter(P)= 2w+2l= 72 (simplify expression: divide each side by 2 )
P= w+l= 36 (plug in "2w" for "l")
P= w+(2w)= 36
P= 3w= 36 (divide each side by 3 to find the width)
w= 12 units

find length:
l=2w
l= 2(12)
l= 24 units

The length of this rectangle is 24 units and the width is 12 units.