khristaviaaa
05.03.2020 •
Mathematics
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 415 grams and a standard deviation of 23 grams. Find the weight that corresponds to each event.
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Ответ:
(a) The highest 20% weight correspond to the weight 434.32 grams.
(b) The middle 60% weight correspond to the weights 434.32 grams and 395.68 grams.
(c) The highest 80% weight correspond to the weight 395.68 grams.
(d) The highest 80% weight correspond to the weight 391.08 grams.
Step-by-step explanation:
Let X = weight of a small Starbucks coffee.
It is provided:
(a)
Compute the value of x fro P (X > x) = 0.20 as follows:
Use a standard normal table.
The value of z is 0.84.
The value of x is:
Thus, the highest 20% weight correspond to the weight 434.32 grams.
(b)
Compute the value of x fro P (x₁ < X < x₂) = 0.60 as follows:
Use a standard normal table.
The value of z is 0.84.
The value of x₁ and x₂ are:
Thus, the middle 60% weight correspond to the weights 434.32 grams and 395.68 grams.
(c)
Compute the value of x fro P (X > x) = 0.80 as follows:
Use a standard normal table.
The value of z is -0.84.
The value of x is:
Thus, the highest 80% weight correspond to the weight 395.68 grams.
(d)
Compute the value of x fro P (X < x) = 0.15 as follows:
Use a standard normal table.
The value of z is -1.04.
The value of x is:
Thus, the highest 80% weight correspond to the weight 391.08 grams.
Ответ:
k = -1.8
Step-by-step explanation:
add 6 to both sides
-4k=7.2
divide both sides by -4
k = -1.8