Shamiyah732
16.10.2020 •
Mathematics
The width of a rectangle is 50% more than the length. The perimeter is 65. Find both dimensions.
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Ответ:
Step-by-step explanation:
Perimeter of rectangle = 2 times width + 2 times length
P= 2W + 2L
Let's say W = width , L= length
We are told the width is 50% more than the length.
width = 0.5 + L
W = 0.5 + L
From here we can say
Perimeter = 2W + 2L so,
P = 2(0.5 + L) + 2L
P = 1 + 2L + 2L
P = 1 + 4L
We are also told perimeter is 65 (P=65)
65 = 1 + 4L
Subtract 1 from both sides
64 = 4L
Divide 64 by 4 to find L
L = 64/4 = 16
Now since we know L= 16, this means
W = 0.5 + L is the same as
W = 0.5 + 16 = 16.5
Therefore Length = 16, width = 16.5
Ответ: