ninaaforever

07.11.2019 • 

Mathematics

The work of a student to solve a set of equations is shown:

equation a: y = 4 – 2z
equation b: 6y = 2 – 4z

step 1: –6(y) = –6(4 – 2z) [equation a is multiplied by –6.]
6y = 2 – 4z [equation b]
step 2: 6y = 4 – 2z [equation a in step 1 is simplified.]
6y = 2 – 4z [equation b]
step 3: 0 = 6 – 6z [equations in step 2 are added.]
step 4: 6z = 6
step 5: z = 1

in which step did the student first make an error?
step 4
step 3
step 2
step 1

Ответ:

jrfranckowiak

09.01.2022

Mathematics

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That would be step 2.

step 1 is correctmultiplying the first equation by -6 which gives you :
-6y = -24 + 12z
but in step 2, the simplifying would be : y = 4 - 2z

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Ответ:

mdaniella522

14.09.2020

Mathematics

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4(2-1)-3(2-2)
4(1)-3(0)
4•1-0
4-0
4

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