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mkn3347
10.10.2019 •
Mathematics
There are 2 red and 5 green balls in a bag. if you randomly choose balls one at a time , with replacement , what is the probability of choosing 2 green balls and then 1 red ball?
a. 2/21
b.20/147
c.50/343
d. 5/21
Solved
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Ответ:
Option C
ANSWER:
The probability of choosing 2 green balls and 1 red ball is![\frac{50}{343}](/tpl/images/0307/9601/d0550.png)
SOLUTION:
Given, there are 2 red and 5 green balls in a bag.
So, there are 7 balls in the bag.
We need to find the probability of choosing 2 green balls and 1 red ball.
Probability of 2 green balls and 1 red ball = probability of 1st green ball
probability of 2nd green ball x probability of 1 red ball.
Now, probability of 1st green ball =![\frac{\text {number of green balls}}{\text {total number of balls}}](/tpl/images/0307/9601/c1bcf.png)
=![\frac{5}{7}](/tpl/images/0307/9601/41028.png)
because we are replacing after every pick.
Now, probability of red ball =![\frac{\text {number of red balls}}{\text {total number of balls}}](/tpl/images/0307/9601/c42ee.png)
Probability of 2 green balls and 1 red ball =![\frac{5}{7} \times \frac{5}{7} \times \frac{2}{7}](/tpl/images/0307/9601/a403a.png)
Hence, the probability of choosing 2 green balls and 1 red ball is![\frac{50}{343}](/tpl/images/0307/9601/d0550.png)
Ответ: