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klysse123
01.07.2019 •
Mathematics
There are 21 animals on farmer cole’s farm — all sheep and chickens. if the animals have a total of 56 legs, how many of each type of animal lives on his farm? write a system of equations, and use the equal values method to solve it.
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Ответ:
sheep usually have 4 legs each
chickens usually have 2 legs each
if c=number of shep and s=number of chickents, then c+s=21
total legs is 56, so 2c+4s=56
system of equations is c+s=21 and 2c+4s=56
equal values method? why do they have to keep changing names, it doesn't sound like subsitution so I'm assuming they mean linear combinations
c+s=21
2c+4s=56
multiply first equation by -2 and add to 2nd equation
-2c-2s=-42
2c+4s=56 +
0c+2s=14
2s=14
divide by 2
s=7
sub back
c+s=21
c+7=21
c=14
14 chickens and 7 sheep
Ответ:
The options look very blurry