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arivalen
25.11.2019 •
Mathematics
There are 39 students in a psychology class. the class has been divided into 10 groups; 9 groups have 4 students in them, 1 group only has 3 students. the instructor puts all of the students names in a hat and then randomly draws 1 name. what are the chances that the one name will be the name of someone in the small, 3-person group?
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Ответ:
Our required probability is 0.1875.
Step-by-step explanation:
Since we have given that
Number of students = 39
Total Number of groups = 10
Number of groups containing 4 students = 9
Number of groups containing 3 students = 1
So, Probability of getting group of 4 students =![\dfrac{9}{10}](/tpl/images/0390/0705/43a86.png)
Probability of getting group of 3 students =![\dfrac{1}{10}](/tpl/images/0390/0705/2af9c.png)
Using the "Bayes theorem":
Probability that the one name will be the name of someone in the small 3-person group is given by
Hence, our required probability is 0.1875.
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Step-by-step explanation: