there are four children in Jana's family. She is less than 11 years old and is the oldest. there's a two-years age difference to twins, riya and seta, who come next. yuvi who is older than 5 is 2 years younger than the twins. how old are each of the children?

Jana=10, twins=8, yuvi=6

Step-by-step explanation:

it's the only possible answer,as we know yuvi is older than 5 so let's just say she is 6 then the twins are 2 years older=8 and we know that and is less then 11 so that would be 10

x = a*y + 3

Step-by-step explanation:

To make x the subject of the equation, first, we open the bracket

4x - 12/a = y

Then cross multiply:

4x - 12 = a * y ( a*y means the product of the two variables)

Add 12 to both sides of the equation

4x = a*y + 12

Divide both sides by 4 to get the value of x

x = a * y + 12/4

x = a*y + 3

I hope this helps.