these marbles are placed in a bag and two of them are randomly drawn. yellow=2 pink=3 blue=5 what is the probability of drawing 2 yellow marbles if the first one is not placed back into the bag before the second one. Give your answer as a rational number, reduced to simplest terms.

1/45

Step-by-step explanation:

From thw question, we are told that there are:

Yellow marbles =2

Pink marbles =3

Blue marbles = 5

Total marbles = 2+3+5 = 10

The probability of drawing the first yellow ball will be= 2/10

Since the ball is not replaced, that means there will be 9 balls left and 1 yellow ball left. Therefore, the probability of drawing the second yellow ball will be = 1/9

The probability of drawing two yellow balls if they're not replaced will now be:

= 2/10 × 1/9

= 2/90

= 1/45

x-1 multiple 2x-1 = f(-x)