This is urgent
(02.03 mc) solve for x: −3|x − 3| = −6 (5 points)
select one: a. x = 1, x = −1 b. x = 1, x = 5 c. x = 0, x = 5 d. no solutions

A. x = 1, x = -1

Step-by-step explanation:

Given the inequality

−3|x − 3| = −6

The equation will give us two solutions due to the nodulus sign. The modulus sign means that the function x- 3 can take both positive and negative value.

If |x-3| is positive, we have:

-3(x+3) = -6

-3x-9 = -6

Moving -9 to the other side:

-3x = -6-(-9)

-3x = -6+9

-3x = 3

x = 3/-3

x = -1

Similarly if |x-3| is negative, we have:

-3{-(x-3)} = -6

-3(-x+3) = -6

3x-9 = -6

3x = -6+9

3x = 3

x = 3/3

x = 1

The solutions are x = -1 and x = 1

To support her discussion it would be best for Alexus to use GRAPH B for her presentation.

Alex should use this graph for her presentation because the number of faulty products APPEARS TO DECREASE LESS on this graph.

Step-by-step explanation: