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cadenhuggins2
23.04.2020 •
Mathematics
This picture of a wall hanging is made of congruent 30° − 60° − 90° triangles with height 6 cm and hypotenuse 12 cm. What is the perimeter of the wall hanging to the nearest tenth of a centimeter?
A. (24+243√) cm ≈ 65.6 cm
B. (12+6) cm = 18.0 cm
C. (144+36) cm = 180 cm
D. (12+123√) cm ≈ 32.8 cm
Solved
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Ответ:
28.4cm
Step-by-step explanation:
Perimeter of the wall will be the sum if all the sides of the right angled triangle.
Given the height of the triangle = 6cm
Hypotenuse = 12cm
Using Pythagoras theorem to get the third side
Hypotenuse² = opposite²+adjacent²
Taking the height as the opposite = 6cm
12² = 6²+adj²
Adj² = 12²-6²
Adj² = 144-36
Adj² = 108
Adj = √108
Adj = 10.39cm
The perimeter of the wall = 6cm+12cm+10.39cm
= 28.39cm
= 28.4cm to nearest tenth.
Ответ:
Take away 1 from each, representing the same book they all read.
7 - 1 = 6 , 6 - 1 = 5 , 5 - 1 = 4
Add the three together.
6 + 5 + 4 = 15
Add that one book everyone read.
15 + 1 = 16 different books.
Hope I helped you out.