Three bags contain 64.2 kg of sugar. the second bag contain 4/5 of the first and third bag contains 45 1/2% of what there is in the second bag. how much sugar is there in each bag

    Mass of sugar in first bag = 29.67 kg

    Mass of sugar in second bag = 23.73 kg

    Mass of sugar in third bag = 10.80 kg

Explanation:

  Total mass of sugar = 64.2 kg

  Let x be the mass of sugar in first bag.

 The second bag contain 4/5 of the first bag

 Mass of sugar in second bag

 Third bag contains 45 1/2% of what there is in the second bag.

 Mass of sugar in third bag

   Total mass of sugar = 64.2 kg = x + 0.8 x + 0.364 x = 2.164 x

                             2.164 x  = 64.2

                                     x = 29.67 kg

    Mass of sugar in first bag =  x = 29.67 kg

    Mass of sugar in second bag =  0.8 x = 23.73 kg

    Mass of sugar in third bag =  0.364 x = 10.80 kg

Since M is the midpoint and has the coordinate (0, 0), therefore the distance of G to M and R to M must be equal. This also means that point M is the average of the coordinates of G and R. Therefore:

(x + -8) / 2 = 0

x = 8

(y + 3) / 2 = 0

y = -3

Therefore point R is located at (8, -3).