Three consecutive integers are such that three times the largest exceeds the sum of the two smaller inte-
gers by 47. Find the integers.

42,43,44

Step-by-step explanation:

yeah-ya right?

Step-by-step explanation:

The three consecutive integers are:

x, x+1 and x+2.

So,

(x+2)*3 > 2x+1.

(x+2)*3 is equal to 3x + 6

so 3x+6-47 = 2x+1

If something +6, then -47, it is the same as -41.

3x-41 = 2x+1

Which is the same as:

3x = 2x+42

So x is 42.

The integers therefore are

42, 43 and 44.

To test this, 44x3 is 132.

42+43=85

132 - 85 is 47.

step-by-step explanation:

if we roll   two fair six-sided dice, then the outcomes to get the sum atleast 9 are: (6,3), (3,6), (6,4), (4,6), (6,5), (5,6), (5,5), (6,6)

thus, the number of outcomes for the sum to be greater than or equal to 9 = 8

the total possible outcomes = 36

then the probability that the sum is 9 or higher is given by : -

hence, the   probability that the sum is 9 or higher is