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rina62
24.02.2020 •
Mathematics
Three dice are rolled. Let the random variable x represent the sum of the 3 dice. By assuming that each of the 63 possible outcomes is equally likely, find the probability that x equals 11.
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Ответ:
In decimal form, 1/8 = 0.125 which converts to 12.5%
Work Shown:
The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.
Here are all of the ways to add to 11 if we had 3 dice
sum = 1+4+6 = 11 sum = 1+5+5 = 11 sum = 1+6+4 = 11 sum = 2+3+6 = 11 sum = 2+4+5 = 11 sum = 2+5+4 = 11 sum = 2+6+3 = 11 sum = 3+2+6 = 11 sum = 3+3+5 = 11 sum = 3+4+4 = 11 sum = 3+5+3 = 11 sum = 3+6+2 = 11 sum = 4+1+6 = 11 sum = 4+2+5 = 11 sum = 4+3+4 = 11 sum = 4+4+3 = 11 sum = 4+5+2 = 11 sum = 4+6+1 = 11 sum = 5+1+5 = 11 sum = 5+2+4 = 11 sum = 5+3+3 = 11 sum = 5+4+2 = 11 sum = 5+5+1 = 11 sum = 6+1+4 = 11 sum = 6+2+3 = 11 sum = 6+3+2 = 11 sum = 6+4+1 = 11There are 27 ways to add to 11 using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.
So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.
Ответ:
For the question that asks what the 20 represents, it reresents the (B) initial dosage in milligrams
Step-by-step explanation: