Three identical coins, labeled a, b, and c in the figure, lie on three corners of a square 10.0 cm on a side. determine the x coordinate of each coin, xa, xb, and xc.

The line of symmetry of the triangle bisects the right angle and the diagonal of the square.
The line is 1/2 the length of the square's diagonal :

(1/2)(10√2) = 5√2. 

Let CG be a distance x from the vertex of the right angle in the triangle.
Remaining distance = 5√2 - x. 

(1)(x) = (2)(5√2 - x)
x = 10√2 - 2x
3x = 10√2 
x = (10/3)√2. 

Using Pythagorean theorem,
x^2 + y^2 = c^2
 
c = (10/3)√2,
and x = y,
so 2x^2 = 200/9
x = √(100/9) = 10/3 = y. 

x = y = 3.333

We know:

a, b, c - the lenght of sides of a triangle

a + b > c; a + c > b; b + c > a

We have:

a = 14 in; b = 4 in

check b + c > a:

c = 10in → 4 + 10 = 14 NOT

c = 11 in → 4 + 11 = 15 > 14

11 in