mgarcia1394
23.06.2019 •
Mathematics
Three positive numbers form an arithmetic progression; their sum is 18. if the first number is increased by 4, then the numbers will form a geometric progression. find the original three numbers in arithmetic progression.
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Ответ:
{4+2√7, 6, 8-2√7}
Step-by-step explanation:
The middle term of three of an arithmetic sequence is the average of the three numbers—their sum divided by 3. So, this arithmetic sequence has a middle term of 6.
If the common difference is x, then the numbers are ...
{6 -x, 6, 6+x}
When the first is increased by 4, to 10-x, then the ratios of adjacent terms are the same:
6/(10-x) = (6+x)/6
36 = 60 +4x -x^2 . . . . . . multiplying by 6(10-x)
x^2 -4x = 24 . . . . . in a form suitable for completing the square
(x -2)^2 = 28 . . . . . . after adding 4
x = 2-2√7 . . . . . the solution that makes the sequence be positive numbers
The arithmetic sequence is then ...
{4 +2√7, 6, 8 -2√7} ≈ {9.2915, 6, 2.7085}
Ответ:
First find the radius by taking half the diameter. Use the radius to find the base area by using the formula for the area of a circle. Find the product of the base area and height, and then take one-third of the product.