Three quarters of the cars in a parking garage are black, 4/7 of the remaining cars are blue, and the rest are silver. If there are 9 silver cars, how many cars are in the parking garage? * 1 point

84 cars

Step-by-step explanation:

Given that 3/4 of the cars in a parking garage are black, let the number of cars in the garage be T, then

number of black cars = 3T/4, other = T - 3T/4 = T/4

If 4/7 of the remaining cars are blue then

the number of blue cars = 4/7 * T/4 = T/7

Remaining cars = T/4 - T/7

= (7T-4T)/28

=3T/28

Given that the remaining cars are sliver and the number of silver cars is 9 then

3T/28 = 9

Cross multiply

3T = 28 * 9

Divide both sides by 3

T = 28 * 9 / 3

= 28 * 3

= 84 Car

k = 1

P(t) = (t + 20)²

Step-by-step explanation:

P' = k√P = k P⁰•⁵

To solve for k,

P' = 10 rabbits/month

P = 100 rabbits

10 = k √100

10 = 10k

k = 1

To solve for P(t)

P' = dP/dt

(dP/dt) = kP⁰•⁵

dP/P⁰•⁵ = k dt

P⁻⁰•⁵ dP = k dt

∫ P⁻⁰•⁵ dP = ∫ k dt

2P⁰•⁵ = kt + c

At t = 0, P = 100

2(100)⁰•⁵ = 0 + c

2 × 10 = c

c = 20

2P⁰•⁵ = kt + c

2P⁰•⁵ = kt + 20

Recall, k = 1

2P⁰•⁵ = t + 20

P⁰•⁵ = (t + 20)

P(t) = (t + 20)²