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graceaowen
04.10.2019 •
Mathematics
Tim tracked the change in outside temperature one afternoon. he recorded a temperature of 85.4 f at noon. the temperature then rose 3.85 f over the next 4 hours. at 5: 00 pm tim recorded a temperature of 89.25 f. how did the temperatue change between 4: 00 pm and 5: 00 pm
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Ответ:
noon 85.4 + 3.85 = 89.25
1st hr 89.25 + 3.85 = 93.1
2nd hr 93.1 + 3.85 = 96.95
3rd hr 96.95 + 3.85 = 100.8
4th hr 100.8 ??
5 pm 89.25
100.8-89.25= 11.55
Ответ:
Ответ: