Mathematics: Tires have a normal distribution with a mean of 7 miles and a standard deviation of 4400 miles. what proportion of tires will last at least 75000 miles.

Tires have a normal distribution with a mean of

Ответ:

miacervenka

31.12.2021

Let T = the distance, in miles, a tire lasts

T ~ N(70000,4400²)

P(T $\geq$ 75000)
= P(Z $\geq \frac{75000 - 70000}{4400}$ )
= P(Z $\geq \frac{25}{22}$ )
≈ P(Z $\geq$ 1.14)
= 1 - P(Z < 1.14)
≈ 1 - 0.8729
= 0.1271

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Ответ:

yonna74

27.05.2022

Mathematics

5/3*1/5= 1/3

Step-by-step explanation:

change the mixed fraction into improper fraction which is 1*3+2=5

then multiply

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Tires have a normal distribution with a mean of 7 miles and a standard deviation of 4400 miles. what proportion of tires will last at least 75000 miles.

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