Mathematics: Today a boat valued at $45,000.thebvalue is expected to decrease at a rate of 8.5% each year.what is the value of the boat expected to be 3 years from now

Mi/hr that is the rate that you want so divide the miles by the time.(3mi/5)/(3hr/8)(3m/5)(8/3hr)8mi/5hr1.6 mph...

Today a boat valued at $45,000.thebvalue is expected

emmmssss21

11.03.2022

Current value of the boat = $45000

Rate at which the value decrease = 8.5%

Value decreased after 1 year = $\frac{8.5}{100}\times45000=3825$

Hence, value becomes = 45000-3825=41175

Value decreased after 2nd year =

$\frac{8.5}{100}\times41175=3499.875$

Hence, value becomes = 41175-3499.875=37675.125

Value decreased after 3 year =

$\frac{8.5}{100}\times37675.125=3202.385$

Hence, value becomes = 37675.125-3202.385=34472.74

So, value of the boat after 3 years becomes $34472.74

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