Mathematics: Town A currently has 10,000 people in the population is growing by 1000 people per year. Town B currently has 9000 people in the population is growing by 10% per year. After how many years will town B first have more people than town A? A.5 years B.6 years C.7 years D.8 years

Town A currently has 10,000 people in the population

yurrrkassi

01.02.2022

Given:

Total fish (Sea bass and mackerel) = $7\dfrac{2}{5}$ pounds

Sea bass = $4\dfrac{5}{8}$ pounds

He gave away $1\dfrac{7}{8}$ pounds of mackerel.

To find:

The remaining mackerel.

Solution:

We know that,

Mackerel = Total fish - Sea bass

$\text{Mackerel}=7\dfrac{2}{5}-4\dfrac{5}{8}$

$\text{Mackerel}=\dfrac{37}{5}-\dfrac{37}{8}$

$\text{Mackerel}=\dfrac{296-185}{40}$

$\text{Mackerel}=\dfrac{111}{40}$

He gave away $1\dfrac{7}{8}$ pounds of mackerel. So, the remaining mackerel is:

$\text{Remaining Mackerel}=\dfrac{111}{40}-1\dfrac{7}{8}$

$\text{Remaining Mackerel}=\dfrac{111}{40}-\dfrac{15}{8}$

$\text{Remaining Mackerel}=\dfrac{111-75}{40}$

$\text{Remaining Mackerel}=\dfrac{36}{40}$

$\text{Remaining Mackerel}=\dfrac{9}{10}$

Therefore, the remaining Mackerel is $\dfrac{9}{10}$ pounds or 0.9 pounds.

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