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BeeShyanne
14.07.2020 •
Mathematics
Translate into an algebraic expressions: a x is increased by 50% and decreased by 30% . What is the result?
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Ответ:
21x/20 or can be written as x + x/20 .
Step-by-step explanation:
The number is x
step 1
x is increased by 50%
value of 50% of x = 50/100 *x = x/2
New value after this change = x + 50% increase = x + x/2 = 3x/2
Step 2 The value obtained is decreased by 30%
value of 30% newly found number is = 30% of value found in step 1
value of 30% newly found number is = 30/100 * 3x/2 = 9x/20
This value (9x/2) is subtracted from value found in step 1(3x/2) as given that value obtained is decreased by 30%
new value found after 30% decrease = 3x/2 - 9x/20 = (3x*10 -9x)/20
new value found after 30% decrease = (30x-9x)/20 = 21x/20
Thus, the result of x is increased by 50% and decreased by 30% is 21x/20 = x + x/20
Ответ:
y=2
Step-by-step explanation:
4y^2-16y+16=0 To "solve" means to find the value of x for which this equation is true.
y^2 -4y + 4 = 0 [divide by 4; this is the same equation]
(y-2)(y-2) = 0 [You may factor or use the quadratic equation]
y=2 and y=2 [the same answer]
Check:
Does (2)2 - 4(2) + 4 = 0 ?
4 - 8 + 4 = 0 ?
0 = 0 ? yes