Translate the sentence into an inequality. Twice the difference of a number and 2 is at least 21. Whoever is correct gets brainliest!

2(c-2) >= 21

Step-by-step explanation:

At least means the smallest number must be, so the symbol is greater than or equal to for 21 to be the smallest possible number.

For twice the difference of a number and 2, we need the difference first, then we multiply by 2, hence 2(c-2).

Combining all of our previous information, 2(c-2) >= 21.

I hope this helps! :)

Step-by-step explanation:

note : -2x²+x+4=0      quadratic equation when : a= -2   b=1   c=4

delta = b² - 4ac

delta =  (1)² - 4(-2)(4) =33

X1 = (-b+sqrt(delta))/2a

X2 = (-b+sqrt(delta))/2a continue