jbainbynn3198
14.07.2020 •
Mathematics
Triangle ABC has coordinates A(0, 0) B(23, 0), and vertex C lying in Quadrant I. The length of side BC = 11 and the sin(angle ABC = 0.768) when rounded to the nearest thousandth. Circle Q is drawn such that each side of triangle ABC is tangent to circle Q at exactly one point, and circle Q is inscribed within triangle ABC. If F is the x-coordinate of point Q, G is the y-coordinate of point Q, and H is the length of the diameter of circle Q, then a/b = (F + G^2 + H^2), where a and b are coprime positive integers. Find a + b.
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Ответ:
-4 < x < 3
Step-by-step explanation:
-5 < 2x + 3 < 9
subtract 3 from all sides
-8 < 2x < 6
divide all sides by 2
-4 < x < 3