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uc22912
04.08.2020 •
Mathematics
TRIANGLE ABC IS DILATED BY A SCALE FACTOR OF 0.5 WITH THE ORIGIN AS THE CENTER OF DILATION, RESULTING IN THE IMAGE TRIANGLE A'B'C. IF A=(2,2). IF A (2,2), B= (4,3) AND C=(6,3), WHAT IS THE LENGTH OF LINE B'C'?
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Ответ:
The length of the line B'C" is 1 unit.
Step-by-step explanation:
Given: Triangle ABC is dilated by a scale factor of 0.5 with the origin as the center of dilation , resulting in the image Triangle A'B'C'.
If A (2,2), B= (4,3) and C=(6,3).
Distance between (a,b) and (c,d):![D=\sqrt{(d-b)^2+(c-b)^2}](/tpl/images/0717/1476/c8dd2.png)
Then, BC![=\sqrt{(3-3)^2+(6-4)^2}](/tpl/images/0717/1476/97e04.png)
Length of image = scale factor x length in original figure
B'C' = 0.5 × BC
= 0.5 × 2
= 1 unit
Hence, the length of the line B'C" is 1 unit.
Ответ:
1) angle MPN = angle MNT | Given
2) angle PMN = angle PMN | Common angles
Step-by-step explanation:
Therefore, by the AA theorem of similarity angle PMN = angle NMT