Triangle sum (3x+1)^0+(10x-11)^0+(3x-2)^0=180

Step-by-step explanation:

Perhaps you want to know the value of x or the measures of the angles?

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Simplifying the given equation, you get ...

  (16x -12)° = 180°

  16x = 192 . . . . . . . divide by °, add 12

  x = 12

  (3x+1)° = (3·12+1)° = 37°

  (10x-11)° = (10·12-11)° = 109°

  (3x-2)° = (3·12-2)° = 34°

x is 12, and the angle measures are 37°, 109°, 34°.