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jackfrost5
21.11.2019 •
Mathematics
Tutoring services: the community college survey of student engagement reports that 46% of the students surveyed rarely or never use peer or other tutoring resources. suppose that in reality 40% of community college students never use tutoring services available at their college. in a simulation we select random samples from a population in which 40% do not use tutoring. for each sample we calculate the proportion who do not use tutoring. if we randomly sample 100 students from this population, the standard error is approximately 5%. would it be unusual to see 46% who do not use tutoring in a random sample of 100 students?
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Ответ:
No, this would not be unusual because 46% is only 1.2 standard errors from 40%
Step-by-step explanation:
Consider the provided information.
The standard error is approximately 5%
Standard error(SE)=0.05
As we know![SE=\frac{\sigma}{\sqrt{n} }](/tpl/images/0384/9810/b612b.png)
Here x=46%=0.46 and μ=40%=0.40
Now use the formula:![z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}](/tpl/images/0384/9810/636ba.png)
Substitute the respective values in the above formula.
Hence, this would not be unusual because 46% is only 1.2 standard errors from 40%
Ответ:
b] the angles created by this intersection between c and d are special because they are equal to each other, to solve for y we shall have:
(5y-29)=(3y+19)
this is because they are vertical angles, hence solving the above we get:
5y-3y=19+29
2y=48
y=48/2
y=24°
c] to solve for ∠7 and ∠8 we proceed as follows;
angles in a straight line add up to 180:
therefore:
(5y-29)+∠7=180
substituting the value of y in the above and solving for ∠7 we get:
(5×24-29)+∠7=180
91+∠7=180
∠7=180-91
∠7=89
but remember that vertical angles are equal to each other, therefore:
∠7=∠8=89°