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hinacat87
08.12.2020 •
Mathematics
Twice a number decreased by 22 is 48. What is the number?
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Ответ:
Given - Twice a no. decrease by 22 is 48
To find - The no.
Solution -
Let the no. be X
According to the question, equation made is -
2x - 22 = 48
2x = 48 + 22
2x = 70
x = 70/2
X= 35
Verification -
35 ×2 - 22 = 48
70 - 22 = 48
48= 48
LHS = RHS
hence proved
Ответ:
So 468n is k*180, where n and k are integers, such that k/n = 468/180 or (the same) k = 468n/180
468=(2^2)(3^2)(13)
180=(2^2)(3^2)(5)
Then 468/180 = 13/5 and k =13n/5
To make K an integer n has to be a multiple of 5. Use 5 and you get
k = 13
n=5
468n = 468(5) = 2340
2340/180 = 13. which means that 2340 is multiple of 180.
Then the solution is n =5.
To make the numerator divisible by the denominator, you need to multiply