sarah02152005
29.11.2019 •
Mathematics
Two bike riders left each other and started to ride in opposite directions. two hours later they were 54 miles apart. if one of them averaged twice the average rate of the other, what was the rate of each?
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Ответ:
The speed of right going rider is 9 mph
The speed of left going rider is 18 mph
Step-by-step explanation:
Given as :
The total distance apart both the riders = 54 miles
Let The speed of right going rider = x mph
and The speed of left going rider = 2 x mph
The Distance cover by right going rider = D miles
The Distance cover by left going rider = 54 - D miles
Total time for both = 2 hours
So, Time =
Or , Distance = speed × Time
For right going rider
D = x × 2
For left going rider
54 - D = 2 x × 2
Or, from first equation
54 - 2 x = 4 x
or, 54 = 4 x + 2 x
or, 6 x = 54
∴ x =
I.e x = 9 mph
So, The speed of right going rider = 9 mph
and The speed of left going rider = 2 × 9 = 18 mph
Hence The speed of right going rider is 9 mph
and The speed of left going rider is 18 mph answer
Ответ:
Should be (B).
8.5
ED2021