Two boxes have the same volume. box 1 has dimensions of 8 ft. by 4 ft. by 3 ft. box 2 has dimensions of 12 ft. by 4ft by 2 ft. the material to make the boxes cost $3.00 per square foot. how much more does box 2 cost than box 1?

You would have to find the surface areas of each box, which would be 8*4 *2, 8*3 *2, and 4*3 *2. That *3, would be the cost, and then surface area of 2 would be 12*4 *2, 12*2 *2, and 2*4 *2. That *3 would again be the cost to make the box. That all would be A=64 + 48 + 24, or 136*3 = $408 to make box A, and box B=96 + 48 + 16 = 160*3 = $480 to make box B. Therefore, box B, or $480 - $408 = $72 more.

6x - 2y > 8

First, solve the inequality (Isolate the y-variable & put it in function format):

Second, graph the function y = 3x - 4 on the graph.

It should be linear.Because the inequality is < and not ≤, the values on the line aren't included in the solution, so your line should be dotted, not solid.

Third, shade in the area below the line(where y-values are smaller).

Since the inequality is <, that means the solutions are smaller than the solutions of the function 3x - 4.