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12.10.2020 •
Mathematics
Two cars travel at the same distance. The first car travel at 50 miles per hour and reaches its destination at t hours. The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car how long does it take for the first car to reach its destination
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Ответ:
It would take the first car 6 hours to reach its destination.
Speed is the ratio of distance to time. It is given by:
Speed = distance /time
Since the two cars travel at the same distance, let d represent this distance.
The first car travel at 50 miles per hour and reaches its destination at t hours. Hence:
50 = d / t
d = 50t (1)
The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car. Hence the time = t - 1. Hence:
60 = d / (t - 1)
d = 60(t - 1)
d = 60t - 60 (2)
Equating both equations gives:
50t = 60t - 60
10t = 60
t = 6 hours
Hence it would take the first car 6 hours to reach its destination
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Ответ:
The first car reaches its destination in 6 hours.
Step-by-step explanation:
Speed of the first car = 50 miles per hour
Time taken = t hours
Distance travelled = Speed × Time = 50 t
Speed of the second car = 60 miles per hour
Time taken = hours
Distance travelled = Speed × Time =
As two cars travel the same distance,
So, the first car reaches its destination in 6 hours.
Ответ:
David has 42, Leah has 19. This makes David having 23 more stamps than Leah.
2 doesn't work because 42 + 23 = 65. That would mean that Leah would have 65. It says David has more than Leah.