dylan102247

26.07.2019 • 

Mathematics

Two children, moe and joe, are allowed to select candy from a plate of nine pieces of candy. moe, being younger, is allowed to choose first but can only take two candies. joe is then allowed to take three of the remaining candies. joe complains that he has fewer choices than moe. is joe correct? how many choices will each child have?

Ответ:

wowihavefun

30.05.2020

Mathematics

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Joe is correct because Moe could choose two pieces but had a nine piece variety where as Joe could only choose from 7 pieces of candy

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Ответ:

brazilmade1

13.04.2021

Mathematics

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The sequence is

1, 1 + 2, 1 + 2 + 3, 1  + 2 + 3 + 4, ...

Each term is the sum of the consecutive numbers from 1 to that number.

The nth term is the sum of the first n numbers:

aₙ = 1 + 2 + 3 + ... + naₙ = 1/2n(1 + n) (formula for sum of the n terms of arithmetic progression with the first term of 1 and common difference of 1)aₙ = n(n + 1)/2

1) The number of circles in the nth pile is n(n + 1)/2

2) When n tends to infinity the number of circles tends to infinity

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