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jameslinimk
20.07.2019 •
Mathematics
Two cubes have surface areas of 72 square feet and 98 square feet. what is the ratio of the volume of the small cube to the volume of the large cube?
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Ответ:
Ratio of the volumes of the cubes = 216 : 343
Step-by-step explanation:
Since surface area of a cube is represented as 6a² where a is the side of a cube.
Let a is one side of large cube and b is the side of smaller one.
Ratio of their surface area =![\frac{6a^{2} }{6b^{2}}=\frac{72}{98}](/tpl/images/0112/1518/600ed.png)
Now ratio of the volumes =![\frac{a^{3} }{b^{3}}=(\frac{1}{b})^{3}](/tpl/images/0112/1518/acb2c.png)
Ratio =![(\frac{6}{7})^{3}=\frac{216}{343}](/tpl/images/0112/1518/0737a.png)
Therefore, ratio of the volumes of the cubes = 216 : 343
Ответ:
1. No solution (the two lines are parallel)
2. One solution (the two lines intersect at one point)