Mathematics: Two equations are given below: a – 3b = 28 a = b – 2 what is the solution to the set of equations in the form (a, b)? (–12, –10) (–15, –13) (–17, –15) (–18, –16)

Two equations are given below: a – 3b = 28 a - id3283809354, sophiateaches053

Ответ:

soloriorafa

10.01.2022

Siince 2nd equation is already equal a, subsitute b-2 for a in the other equation

b-2-3b=28
-2-2b=28
add 2 to both sides
-2b=30
divide both sides by -2
b=-15
sub back
a=b-2
a=-15-2
a=-17

(a,b)
(-17,-15)

3rd choice

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Ответ:

greeneashlynt

23.04.2023

Mathematics

The answer is D. since you need to find the radius you would divide 5.7 by two which is 2.85. but since you are leaving it in terms of pi would you keep it as 5.7 since circumference of a
circle is 2*pi*r

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Two equations are given below:

a – 3b = 28
a = b – 2

what is the solution to the set of equations in the form (a, b)?

(–12, –10)
(–15, –13)
(–17, –15)
(–18, –16)

Ответ:

Ответ:

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