Mathematics: Two fair, six-sided number cubes are rolled. what is the probability that the sum of the values shown is less than 4? 2/3 1/12 1/4 1/3

Two fair, six-sided number cubes are rolled. what

Officaljazz18

13.03.2022

$\frac{1}{12}$

Step-by-step explanation:

Let S be the sample space, when two fair six-sided number cubes are rolled.

The sample space is in attached pic.

Let E be the event when sum of the values is less than 4.

$E=\left \{ (1,1), (1,2), (2,1) \right \}$

We know that $P(E)=\frac{n(E)}{n(S)}$ i.e $P(E)=\frac{number\:of\:elements\:in\:E}{number\:of\:elements\:in\:S}$

So, $P(E)=\frac{3}{36}=\frac{1}{12}$

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dianaosorio33895

18.11.2022

Answer : 45 centimeters
Explanation: 756 = ((a+b)/2)h
756 = ((39+b)/2)18
756/18 = (39+b)/2
42= (39+b)/2
2(42) = 39 + b
84 = 39+b
84-39=b
45=b

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