Two forces act on a hook. the magnitude are f1=300n toward the positive x-axis and f2=125n at a 48 degree angle to the x-axis. find the direction and the magnitude of the resultant force ?

Horizontal components:
 F1x = 300
 F2x = 125 * cos (48) = 83.64132579
 horizontal net force:
 Fx = 83.64132579 + 300
 Fx = 383.6413258 N
 Vertical components:
 F2y = 125 * sine (48) = 92.89310318
 vertical net force:
 Fy = 92.89310318
 Magnitude of the resulting force:
 F = root ((Fx) ^ 2 + (Fy) ^ 2)
 F = root ((383.6413258) ^ 2 + (92.89310318) ^ 2)
 F = 125
 Angle:
 theta = Atan (Fy / Fx)
 theta = Atan (92.89310318 / 383.6413258)
 theta = 13.61 degrees
 
 The direction and the magnitude of the resultant force are:
 F = 125 N
 theta = 13.61 degrees

The interest in the year 12 will be 129.
substitute x for 12 and complete the order of operations and you should get 129 as an answer