kelsgoat22
17.10.2020 •
Mathematics
Two shooters, Rodney and Philip, practice at a shooting range. They fire 100 rounds each at separate targets. The targets are marked with circles and each bullet hitting a particular circle gets them a particular number of points. 60 rounds are selected at random. The sample mean scores of Rodney and Philip are 8 and 10, respectively. And, their variances are 0.25 and 0.50, respectively The standard error of the difference between their mean scores is (Round your answer to two decimal places.) The 95% confidence interval for the difference between the mean scores Rodney and Philip is : (Enter a minus sign if your answer is negative. Round your answer to two decimal places.)
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Ответ:
A) SE = 0.1118
B) 95% Confidence interval is;
-2.22 < μ1 - μ2 < -1.78
Step-by-step explanation:
We are given;
Sample size; n = 60
Sample mean 1; x1 = 8
Sample mean 2; x2 = 10
Variance 1; v1 = 0.25
Variance 2; V2 = 0.5
Now,
Standard deviation is given by the formula ;
σ = √variance
Thus;
σ1 = √0.25
σ1 = 0.5
σ2 = √0.5
σ2 = 0.7071
Formula for standard error of mean is;
SE = σ/√n
Thus;
SE1 = 0.5/√60
SE1 = 0.06455
SE2 = 0.7071/√60
SE2 = 0.0913
The standard error of the difference between their mean scores would be;
SE = √[(SE1)² + (SE2)²]
SE = √(0.06455² + 0.0913²)
SE = 0.1118
Formula for 95% confidence interval is;
(x1 - x2) - ((Z_α/2) × SE) < μ1 - μ2 < (x1 - x2) + ((Z_α/2) × SE)
Where Z_α/2 is the critical value. At confidence interval of 95%, we have a critical value of 1.96 from tables.
Thus, plugging in the relevant values, we have;
(8 - 10) - (1.96 × 0.1118) < μ1 - μ2 < (8 - 10) + (1.96 × 0.1118)
-2.22 < μ1 - μ2 < -1.78
Ответ:
True
A coefficient is a number that looks like this 5x
Hope this works