Mathematics: Two solutions of differently concentrations of acid are mixed creating 40 ml of a soul union that is 32% acid one-quarter of the soulutiob is made up of 20% acid soulution. the remaining three quarters is made up of a solution of unknown concentration c. which equation can be used to determine c, the unknown.

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Two solutions of differently concentrations of acid

Isaiahplater27

13.01.2022

Three quarters (30 ml) is made up of a 36% acid solution.

Step-by-step explanation:

Since we have given that

Total amount of solution = 40 ml

One- quarter of the solution is given by

$\frac{1}{4}\times 40\ ml\\\\=10\ ml$

Three-quarter of the solution is given by

$\frac{3}{4}\times 40\\\\=30\ ml$

According to question, we have

10 ml of solution is made up of = 20% of acid solution

30 ml of solution is made up of = say 'c ' of acid solution

40 ml of solution is made up of = 32 % of acid solution

So, our equation becomes,

$10\times 0.2+30\times c=40\times 0.32\\\\2+30c=12.8\\\\30c=12.8-2\\\\30c=10.8\\\\c=\frac{10.8}{30}\\\\c=0.36\\\\c=36\%$

Hence, three quarters (30 ml) is made up of a 36% acid solution.

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