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cubist7472
21.02.2021 •
Mathematics
Un gros rouleau de tissus de 3 m de
large a une longueur de tissus totale de
14 dam.
Ce tissus se vend 1,26 $ le mètre carré.
Quelle est la valeur totale du rouleau de
tissus?
Solved
Show answers
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Ответ:
Tan(α)=Opposite/Adjacent
α=30º
Opposite=16
Adjacent=h
2. When you substitute these values into Tan(α)=Opposite/Adjacent, you obtain:
Tan(α)=Opposite/Adjacent
Tan(30º)=16/h
3. Now, you must clear "h":
h(Tan(30º))=16
h=16/Tan(30º)
h=27.7
4. The value of "x" is:
Cos(β)=Adjacent/Hypotenuse
β=41º
Adjacent=h=27.7
Hypotenuse=x
5. When you substitute these values into Cos(β)=Adjacent/Hypotenuse, you have:
Cos(β)=Adjacent/Hypotenuse
Cos(41º)=27.7/x
6. You must clear "x", as below:
x(Cos(41º))=27.7
x=27.7/Cos(41º)
7. Therefore, the lenght "x" is:
x=36.70