kleshead
06.05.2020 •
Mathematics
Un objeto se mueve sobre una recta de acuerdo a la ecuacio n s(t) =3t^2 _ 8t + 7 donde s se mide en cm y t en segundos. Hallar la velocidad del objeto cuando t=1 y cuando t=5
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Ответ:
(3x^3 - 5x - 8) + (5x^3 + 7x + 3) = 3x^3 - 5x - 8 + 5x^3 + 7x + 3 = 8x^3 + 2x - 5
The correct result would be 8x^3 + 2x - 5.