liddopiink1
24.03.2020 •
Mathematics
Until recently hamburgers at the city sports arena cost $4 each. The food concessionaire sold an average of 10,000 hamburgers on a game night. When the price was raised to $4.40, hamburger sales dropped off to an average of 8,000 per night. Assuming a linear demand curve, find the price of a hamburger that will maximize the nightly hamburger revenue. If the concessionaire has a fixed cost of $1000 per night and the variable cost is $0.60 per hamburger, find the price of a hamburger that will maximize the nightly hamburger profit.
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Ответ:
y+5=-1/3(x+3)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-5)=-1/3(x-(-3))
y+5=-1/3(x+3)