Use elimination to solve each system of equations
2x-y=-1
3x-2y=1

2x - y = -1
3x - 2y = 1
5x - 3y = 0
5x - 5x - 3y = 0 - 5x
3y = 0 - 5x
3y = 0 - 5x
 3        3
y = 0 - 5/3x
3x - 2(0 - 5/3x) = 1
3x + 8/3x = 1
5 1/4x = 1
5 1/4x =  1   
5 1/4    5 1/4
     x = 4/21
3(4/21) - 2y = 1
 4/7 - 2y = 1
-4/7         -4/7
         -2y = 3/7
         -2y = 3/7
          -2      -2
           y = -3/14
(x, y) = (4/21, -3/14)

(10, –1)

Step-by-step explanation:

[1]3y=−12x+2

[2]y=−x+9

While it is not technically necessary, I find it easier to clear the fractions before actually beginning; so multiplying [1] by 2

[3]6y=−x+4

Substituting (from [2]) (−x+9) for y in [3]

[4]6(−x+9)=−x+4

Simplifying

[5]−6x+54=−x+4

[6]5x=50

[7]=10

Substituting (from [7]) 10 for x in [2]

[8]y=−10+9=−1