Use pascal s triangle or the binomial theorem

Ответ:

ana9340

31.12.2021

$(3c-2d)^4=(3c)^4-4(3c)^3\cdot2d+6\cdot(3c)^2\cdot(2d)^2-4\cdot3c\cdot(2d)^3-(2d)^4\\\\=81c^4-216c^3d+216c^2d^2-96cd^3-16d^4\\-------------------------------\\(2n+3)^2\\=(2n)^5+5(2n)^4\cdot3+10(2n)^3\cdot3^2+10(2n)^2\cdot3^3+5\cdot2n\cdot3^4+3^5\\\\=32n^5+240n^4+720n^3+1080n^2+810n+243\\-------------------------------\\(x^2+4)^3=(x^2)^3+3(x^2)^2\cdot4+3x^2\cdot4^2+4^3\\\\=x^6+12x^4+48x^2+64$
Use pascal's triangle or the binomial theorem to expand the binomials. 1. (3c-2d)^4 2. (2n+3)^5 3.

Use pascal's triangle or the binomial theorem to expand the binomials. 1. (3c-2d)^4 2. (2n+3)^5 3.

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Ответ:

Lcorbett7414

26.06.2022

Mathematics

grinding points here

Step-by-step explanation:

sry for not being helpful

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Use pascal's triangle or the binomial theorem to expand the binomials.
1. (3c-2d)^4
2. (2n+3)^5
3. (x^2+4)^3

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Use pascal's triangle or the binomial theorem to expand the binomials. 1. (3c-2d)^4 2. (2n+3)^5 3. (x^2+4)^3

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Use pascal's triangle or the binomial theorem to expand the binomials.
1. (3c-2d)^4
2. (2n+3)^5
3. (x^2+4)^3