Use the distributive property to find the products for 3-11 3: (x+1) (x+3) 4: (y+6) (y+4) 5: (z-5) (z+3) 6: (a+8) (a-3) 7: (g-7) (g-2) 8: (n-6) (n-4) 9: (3m+1) (m+9) 10: (2p-4) (3p+2) 11: (6-5s) (2-s)

3: (X + 1) (X + 3)
    = (x + 1)(x + 3)
    = (x)(x) + (x)(3) + (1)(x) + (1)(3)
    
    = X^2 + 3X + X + 3
    = X^2  + 4x  + 3

4:
(y + 6) (y + 4)
= (y + 6)(y + 4)
= (y)(y) + (y)(4) + (6)(y) + (6)(4)

= y^2 + 4y  + 6y + 24
= y^2 + 10y + 24

5:
(z - 5) ( (z + 3)
= (z +  - 5)(z + 3)
= (z)(z) + (z)(3) + ( - 5)(z) + ( - 5)(3)

= z^2 + 3z - 5z - 15
= z^2 - 2z - 15

6:
(a + 8) (a -3)
= (a + 8)(a +  - 3)
= (a)(a) + (a)( - 3) + (8)(a) + (8)( - 3)

= a^2 - 3a + 8a - 24
= a^2 + 5a - 24

7:
(g - 7) ( g - 2)
= (g +  - 7)(g  +  - 2)
= (g)(g) + (g)( - 2) + ( - 7)(g) + ( - 7)( - 2)

= g^2 - 2g - 7g + 14
= g^2 - 9g + 14

8:
(n - 6) (n - 4)
(n +  - 6)( n +  - 4)
= (n)(n) + (n)( - 4) + ( - 6)( n) + (- 6)( - 4)

= n^2 - 4n - 6n + 24
= n^2 - 10n + 24

9:
(3m + 1) ( m + 9)
= (3m + 1)(m + 9)
= (3m)(m) + (3m)(9) + (1)(m) + (1)(9)

= 3m^2 + 27m + m + 9
= 3m^2 + 28m + 9

10:
(2p - 4) ( 3p + 2)
= (2p +  - 4)(3p + 2)
= (2p)(3p) + (2p)(2) + ( - 4)(3p) + (- 4)(2)

= 6p^2 + 4p - 12p - 8
= 6p^2 - 8p - 8

11:
(6 - 5s) (2 - s)
= (6 +   - 5s)(2 +  - s)
= (6)(2) + (6)( - s) + ( - 5s)(2) + (- 5s)( - s)

= 12 - 6s - 10s + 5s^2
= 5s^2 - 16s + 12

Hope that helps wowzah….my brain is tired nowhave a good day...

hi there

Step-by-step explanation: