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hewonabi123
31.03.2021 •
Mathematics
Use the figure below to determine the exact value of the given function sin2 0
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Ответ:
sin2θ =![\frac{12}{13}](/tpl/images/1232/2577/05550.png)
Step-by-step explanation:
Since, sin2θ = 2sinθcosθ
From the triangle given in the picture,
Opposite side of angle θ = 2 units
Adjacent side of angle θ = 3 units
Hypotenuse =
=
[By Pythagoras theorem]
sinθ =![\frac{\text{Opposite side}}{\text{Hypotenuse}}](/tpl/images/1232/2577/ef708.png)
=![\frac{2}{\sqrt{13}}](/tpl/images/1232/2577/18c51.png)
cosθ =![\frac{\text{Adjacent side}}{\text{Hypotenuse}}](/tpl/images/1232/2577/28977.png)
=![\frac{3}{\sqrt{13} }](/tpl/images/1232/2577/51c3b.png)
sin2θ =![2\times (\frac{2}{\sqrt{13}})(\frac{3}{\sqrt{13}})](/tpl/images/1232/2577/d78cc.png)
=![\frac{12}{13}](/tpl/images/1232/2577/05550.png)
Ответ: